25x^2-3x-22=0

Solution for 25x^2-3x-22=0 equation:

25x^2-3x-22=0

a = 25; b = -3; c = -22;
Δ = b2-4ac
Δ = -32-4·25·(-22)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-47}{2*25}=\frac{-44}{50}
=-22/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+47}{2*25}=\frac{50}{50}
=1
$